ВПР 1 №48 Алгебра = ВПТ 3 №11 Математика
Спростіть вираз:
1. $\frac{12a}{5b^2}:\frac{16a}{15b};$
2. $-\frac{7m^2}{n^2}:\frac{21m}{n^3};$
3. $-\frac{5a^3}{4b^2}:\left(-10a^2\right);$
4. $20m^2n:\left(-\frac{4m^3}{p}\right);$
5. $\frac{5c^2}{9m^3}:\frac{25c^3}{81m};$
6. $-\frac{22x^2}{39a}:\left(-\frac{33x^3}{26a^4}\right).$
Розв'язок:
1. $\frac{12a}{5b^2}:\frac{16a}{15b}=\frac{12a\cdot15b}{5b^2\cdot16a}=\frac{9}{4b};$
2. $-\frac{7m^2}{n^2}:\frac{21m}{n^3}=-\frac{7m^2\cdot n^3}{n^2\cdot21m}=$
$= -\frac{mn}{3};$
3. $-\frac{5a^3}{4b^2}:\left(-10a^2\right)=$
$= \frac{5a^3}{4b^2}:\frac{10a^2}{1}=\frac{5a^3}{4b^2\cdot10a^2}=$
$= \frac{a}{8b^2};$
4. $20m^2n:\left(-\frac{4m^3}{p}\right)=-\frac{20m^2n\cdot p}{4m^3}=$
$= -\frac{5np}{m};$
5. $\frac{5c^2}{9m^3}:\frac{25c^3}{81m}=\frac{5c^2\cdot81m}{9m^3\cdot25c^3}=\frac{9}{5m^2c};$
6. $-\frac{22x^2}{39a}:\left(-\frac{33x^3}{26a^4}\right)=$
$= \frac{22x^2\cdot26a^4}{39a\cdot33x^3} = \frac{4a^3}{9x}.$