№ 21 Алгебра = № 21 Математика
Виконайте множення:
1) t(3 – c);
2) –x(p – 2);
3) a(t – b – 9).
Розв'язок:
1) t(3 – c) = t ⋅ 3 – t ⋅ c = 3t − tc;
2) –x(p – 2) = −x ⋅ p + x ⋅ 2 = −xp + 2x;
3) a(t – b – 9) = a ⋅ t – a ⋅ b – a ⋅ 9 = at – ab − 9a.
№ 21 Алгебра = № 21 Математика
1) t(3 – c);
2) –x(p – 2);
3) a(t – b – 9).
1) t(3 – c) = t ⋅ 3 – t ⋅ c = 3t − tc;
2) –x(p – 2) = −x ⋅ p + x ⋅ 2 = −xp + 2x;
3) a(t – b – 9) = a ⋅ t – a ⋅ b – a ⋅ 9 = at – ab − 9a.